-0.125x^2+0.35x+0.75=0

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Solution for -0.125x^2+0.35x+0.75=0 equation: 



-0.125x^2+0.35x+0.75=0

a = -0.125; b = 0.35; c = +0.75;
Δ = b2-4ac
Δ = 0.352-4·(-0.125)·0.75
Δ = 0.4975
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.35)-\sqrt{0.4975}}{2*-0.125}=\frac{-0.35-\sqrt{0.4975}}{-0.25}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.35)+\sqrt{0.4975}}{2*-0.125}=\frac{-0.35+\sqrt{0.4975}}{-0.25}
$

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